Theoretical Aspects of Lexical Analysis/Exercise 2
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Use Thompson's algorithm to build the NFA for the following regular expression. Build the corresponding DFA and minimize it.
- (a*|b*)*
Solution
NFA
The following is the result of applying Thompson's algorithm.
<graph> digraph nfa {
{ node [shape=circle style=invis] start } rankdir=LR; ratio=0.5 node [shape=doublecircle,fixedsize=true,width=0.2,fontsize=10]; 11 node [shape=circle,fixedsize=true,width=0.2,fontsize=10]; start -> 0 0 -> 1; 0 -> 11 1 -> 2; 1 -> 6 2 -> 3; 2 -> 5 3 -> 4 [label="a",fontsize=10] 4 -> 3; 4 -> 5 5 -> 10 6 -> 7; 6 -> 9 7 -> 8 [label="b",fontsize=10] 8 -> 7; 8 -> 9 9 -> 10 10 -> 1; 10 -> 11 fontsize=10 //label="NFA for (a*|b*)*"
} </graph>
DFA
Determination table for the above NFA:
In | α∈Σ | move(In, α) | ε-closure(move(In, α)) | In+1 = ε-closure(move(In, α)) |
---|---|---|---|---|
- | - | 0 | 0, 1, 2, 3, 5, 6, 7, 9, 10, 11 | 0 |
0 | a | 4 | 1, 2, 3, 4, 5, 6, 7, 9, 10, 11 | 1 |
0 | b | 8 | 1, 2, 3, 5, 6, 7, 8, 9, 10, 11 | 2 |
1 | a | 4 | 1, 2, 3, 4, 5, 6, 7, 9, 10, 11 | 1 |
1 | b | 8 | 1, 2, 3, 5, 6, 7, 8, 9, 10, 11 | 2 |
2 | a | 4 | 1, 2, 3, 4, 5, 6, 7, 9, 10, 11 | 1 |
2 | b | 8 | 1, 2, 3, 5, 6, 7, 8, 9, 10, 11 | 2 |
Graphically, the DFA is represented as follows:
<graph> digraph dfa { { node [shape=circle style=invis] start } rankdir=LR; ratio=0.5 node [shape=doublecircle,fixedsize=true,width=0.2,fontsize=10]; 0 1 2 node [shape=circle,fixedsize=true,width=0.2,fontsize=10]; start -> 0 0 -> 1 [label="a"] 0 -> 2 [label="b"] 1 -> 1 [label="a"] 1 -> 2 [label="b"] 2 -> 1 [label="a"] 2 -> 2 [label="b"] fontsize=10 //label="DFA for (a|b)*" } </graph> Given the minimization tree to the right, the final minimal DFA is: <graph> digraph dfamin { { node [shape=circle style=invis] start } rankdir=LR; ratio=0.5 node [shape=doublecircle,fixedsize=true,width=0.4,fontsize=10]; 012 node [shape=circle,fixedsize=true,width=0.2,fontsize=10]; start -> 012 012 -> 012 [label="a"] 012 -> 012 [label="b"] fontsize=10 //label="DFA for (a|b)*" } </graph> |
The minimization tree is as follows. As can be seen, the states are indistinguishable.
<graph> digraph mintree { node [shape=none,fixedsize=true,width=0.2,fontsize=10] " {0, 1, 2}" -> "{}" [label="NF",fontsize=10] " {0, 1, 2}" -> "{0, 1, 2}" [label=" F",fontsize=10] "{0, 1, 2}" -> "{0, 1, 2} " [label=" a,b",fontsize=10] fontsize=10 //label="Minimization tree" } </graph> |
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